Ratio And Proportion Word Problems  Aptitude Questions – MCQ Shortcut Tricks
Ratio And Proportion
Before solving Ratio and
Proportion Word Problems, you must know what Ratio and Proportion is.
Various competitive examinations contain Ratio and Proportion Questions based
on Class 6 to 10 syllabuses. Here are going to provide, ratio and proportion
mixture problems, ratio proportion and variation problems with solutions, ratio
and proportion word problems worksheet and many other Ratio and Proportion
Aptitude Questions. This page is not only useful for the students of class 6 to
10 but is also helpful for the individual who are preparing for any competitive
or entrance exam. Shortcut tricks to solve ratio and proportion problems will
help you in upcoming Bank PO and other exams.
If you want to appear for Bank,
SSC, Railway and other competitive examinations, then you must know Ratio and
Proportion Concepts. This page contains ratio and proportion problems for Bank
PO, ratio and proportion problems for class 6, ratio and proportion problems
for class 7, ratio and proportion problems and solutions for class 9, ratio and
proportion problems for class 8 and others. Also, this page contains ratio and proportion
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Ratio And Proportion Formula
Below Ratio And Proportion Basics
Concepts are given. All the questions of Ratio And Proportion are solved with
the help of these Basics Concepts. You have to apply one or more concepts to
solve Ratio And Proportion Sums in competitive examination or Class 6 to 10
Examination. These formulas will be used to solve all type of Ratio And
Proportion Problems.
Ratio:
 The ratio of two quantities p and q is defined as the fraction and we write it as p: q.
 In the ratio p : q, we call p as the first term or antecedent and q, the second term or consequent.
Eg. The ratio 3 : 4 represents 3/4 with antecedent = 5,
consequent = 9.
Rule: The multiplication or division of each term of a ratio
by the same nonzero number does not affect the ratio.
Eg. 3 : 4 = 9 : 12 = 12: 16 Also, 6 : 3 = 2 : 1.
Proportion:
 The equality of two ratios is called proportion.
 If p : r = r : s, we write p : q :: r : s and we say that p, q, r, s are in proportion.
 Here p and s are called extremes, while q and r are called mean terms.
Ratio And Proportion
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Ratio And Proportion Problems And Solution
Ratio and
Proportion Methods Shortcut Tricks
To appear in any competitive or
entrance exam is very important to know Ratio and Proportion shortcut tricks.
To crack competitive exam you just need to know how to do time management. Time
can managed in exams if you know the short cut tricks. Contenders can go
through Shortcut Tricks of Ratio and Proportion and start practicing Ratio and
Proportion questions with Shortcut Tricks. Anything we learn in our school days was
basics and that is well enough for passing our school exams. Now the time has
come to learn for our competitive exams. For this we need our basics but also
we have to learn something new. That’s where shortcut tricks and formula are
comes into action.
Ratio And Proportion Problems And Solution
You can know how to Solve Ratio
and Proportion by going through ratio and proportion problems with solutions those
are given below. Different concepts are used in these Ratio And Proportion
Aptitude Questions. Some of the questions are based on Ratio And Proportion
Basics and in some questions tricks are used. Let’s get started with ratio and
proportion problems with answers:
Ratio And
Proportion Questions and Answer
You can know How to Solve Ratio
and Proportion by going through Ratio And Proportion Questions that are given
below. Different concepts are used in these Ratio And Proportion Aptitude
Questions. Some of the questions are based on Ratio And Proportion Basics and in
some questions tricks are used.
1. A and B
together have Rs. 1210. If 4/15 of A's amount is equal to 2/5 of B's amount,
how much amount does B have?
A. Rs. 460
B. Rs. 484
C. Rs. 550
D. Rs. 664
Answer: B
Explanation:
(4/15) A = (2/5)B
A = (2/5 x 15/4) B
A = (3/2) B
A/B = 3/2
A : B = 3 : 2.
B's share = Rs. (1210 x 2/5) = Rs. 484.
2. If 0.75 : x :: 5 : 8, then x is equal to:
A. 1.12
B. 1.2
C. 1.25
D. 1.30
Answer: B
Explanation:
(x x 5) = (0.75 x 8) x = (6/5) = 1.20
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to Prepare for Maths Exam
3. Two numbers are
respectively 20% and 50% more than a third number. The ratio of the two numbers
is:
A. 2 : 5
B. 3 : 5
C. 4 : 5
D. 6 : 7
Answer: Option C
Explanation:
Let the third number be x.
Then, first number = 120% of x = 120x/100 = 6x/5
Second number = 150% of x = 150x/100 = 3x/2
Ratio of first two numbers =
(6x/5 : 3x/2) = 12x : 15x = 4 : 5.
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4. The ratio of
the number of boys and girls in a college is 7 : 8. If the percentage increase
in the number of boys and girls be 20% and 10% respectively, what will be the
new ratio?
A. 8 : 9
B. 17 : 18
C. 21 : 22
D. Cannot be determined
Answer: C
Explanation:
Originally, let the number of boys and girls in the college
be 7x and 8x respectively.
Their increased number is (120% of 7x) and (110% of 8x).
= (120 /100 x 7x) and
(110/100 x 8x)
= 42x/5 and 44x/5
= The required ratio = (42x/5 : 44x/5) = 21 : 22
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5. Seats for
Mathematics, Physics and Biology in a school are in the ratio 5 : 7 : 8. There
is a proposal to increase these seats by 40%, 50% and 75% respectively. What
will be the ratio of increased seats?
A. 2
: 3 : 4
B. 6
: 7 : 8
C. 6
: 8 : 9
D. None
of these
Answer: A
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6. If Rs. 782 be
divided into three parts, proportional to
: : , then the first part is:
A. Rs. 182
B. Rs. 190
C. Rs. 196
D. Rs. 204
Answer: D
Explanation:
Given ratio =1/2 : 2/3 : 3/4
= 6 : 8 : 9.
1st part = Rs. 782 x 6/23 = Rs. 204
Explanation:
Originally, let the number of seats for Mathematics, Physics
and Biology be 5x, 7x and 8x respectively.
Number of increased seats are (140% of 5x), (150% of 7x) and
(175% of 8x).
= (140/100 x 5x), (150/100 x 7x) and (175/100 x 8x)
= 7x, 21x/ 2 and 14x.
The required ratio = 7x : 21x /2: 14x
= 14x : 21x : 28x
= 2 : 3 : 4.
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to Prepare For Written Exam
7. In a mixture 60
litres, the ratio of milk and water 2 : 1. If this ratio is to be 1 : 2, then
the quanity of water to be further added is:
A. 20 litres
B. 30 litres
C. 40 litres
D. 60 litres
Answer: Option D
Explanation:
Quantity of milk = (60 x 2/3 litres)
= 40 litres.
Let Quantity of water in it = (60 40) litres = 20 litres.
New ratio = 1 : 2
Explanation:
Let quantity of water to be added further be x litres.
Then, milk : water = 40/
(20 + x)
Now, 40/ (20 + x) = 12
20 + x 80
20 + x = 80
x = 60.
Quantity of water to be added = 60 litres.
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8. A sum of money
is to be distributed among A, B, C, D in the proportion of 5 : 2 : 4 : 3. If C
gets Rs. 1000 more than D, what is B's share?
A. Rs. 500
B. Rs. 1500
C. Rs. 2000
D. None of these
Answer: C
Explanation:
Let the shares of A, B, C and D be Rs. 5x, Rs. 2x, Rs. 4x
and Rs. 3x respectively.
Then, 4x  3x = 1000
x = 1000.
B's share = Rs. 2x =
Rs. (2 x 1000) = Rs. 2000.
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9. The fourth
proportional to 5, 8, 15 is:
A. 18
B. 24
C. 19
D. 20
Answer: B
Explanation:
Let the fourth proportional to 5, 8, 15 be x.
Then, 5 : 8 : 15 : x
5x = (8 x 15)
x = (8 x 15)/ 5 = 24.
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10. Salaries of
Ravi and Sumit are in the ratio 2 : 3. If the salary of each is increased by
Rs. 4000, the new ratio becomes 40 : 57. What is Sumit's salary?
A. Rs. 17,000
B. Rs. 20,000
C. Rs. 25,500
D. Rs. 38,000
Answer: D
Explanation:
Then, (2x + 4000)/ (3x
+ 4000) = 40/ 57
= 57(2x + 4000) = 40(3x + 4000)
= 6x = 68,000
= 3x = 34,000
Sumit's present salary = (3x + 4000) = Rs.(34000 + 4000) =
Rs. 38,000.
11. The sum of
three numbers is 98. If the ratio of the first to second is 2 :3 and that of
the second to the third is 5 : 8, then the second number is:
A. 20
B. 30
C. 48
D. 58
Answer: B
Explanation:
Let the three parts be A, B, C. Then,
A : B = 2 : 3 and B : C = 5 : 8 =(5 x 3/5) : (8 x 3/5) = 3 : 24/5
A : B : C = 2 : 3 :24/5 = 10 : 15 : 24
B = 98 x 15/49 = 30
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12. The salaries
A, B, C are in the ratio 2 : 3 : 5. If the increments of 15%, 10% and 20% are
allowed respectively in their salaries, then what will be new ratio of their
salaries?
A. 3 : 3 : 10
B. 10 : 11 : 20
C. 23 : 33 : 60
D. Cannot be determined
Answer: C
Explanation:
Let A = 2k, B = 3k and C = 5k.
A's new salary = 115/100 of 2k = 115/100 x 2k = 23k/10
B's new salary = 110/100 of 3k = 110/100 x 3k = 33k/10
C's new salary = 120/100of 5k = 120/100 x 5k = 6k
New ratio 23k/10: 33k/10 : 6k = 23 : 33 : 60
13. Two number are
in the ratio 3 : 5. If 9 is subtracted from each, the new numbers are in the
ratio 12 : 23. The smaller number is:
A. 27
B. 33
C. 49
D. 55
Answer: B
Explanation:
Let the numbers be 3x and 5x.
Then, (3x – 9)/(5x –
9) = 12/23
23(3x  9) = 12(5x  9)
9x = 99
x = 11.
The smaller number = (3 x 11) = 33.
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14. If 40% of a
number is equal to twothird of another number, what is the ratio of first
number to the second number?
A.2 : 5
B. 3 : 7
C. 5 : 3
D. 7 : 3
Answer: C
Explanation:
Let 40% of A = 2/3 B
Then, 40A/100 = 2B/3
2A/5 = 2B/3
A/ B = (2/3 x 5/2) = 5/3
A : B = 5 : 3.
15. In a bag, there
are coins of 25 p, 10 p and 5 p in the ratio of 1:2:3. If there is Rs. 30 in
all, how many 5 p coins are there?
A. 50
B. 100
C. 150
D. 200
Answer: C
Explanation:
Let the number of 25 p, 10 p and 5 p coins be x, 2x, 3x
respectively.
Then, sum of their values = Rs. 25x/100 + (10 x 2x)/ 100 + (5
x 3x)/ 100 = Rs. 60x /100
60x/100 = 30 x = (30 x 100)/ 60 = 50
Hence, the number of 5 p coins = (3 x 50) = 150.
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