Problems on Ages Formulas, Important Shortcuts Tricks for Bank/SSC/UPSC
Problems on Ages Formulas
Candidates who are preparing for the Bank/SSC/UPSC
exams can get the shortcuts tricks to solve the Problems on Age Formulas here. In
every competitive exam, there is Quantitative Aptitude section in which
questions related to time, distance and age formulas are being asked. There are
some students who have problems on age formulas at the time of examination because
they do not know the important short tricks. It becomes very difficult for the
candidates who don’t know the formulas and shortcuts to complete the question
paper at a given time period.
If you want to crack the
Bank/SSC exam and score some good marks then it is necessary for you to practice
the formulas daily. Make a time table and cover all the important topics from
the sample papers and models which are easily available at the books shops. We
are providing the important tricks so that you can solve the Problems on age
formulas easily.
Important
Shortcuts Tricks for Bank/SSC/UPSC
To solve all the sections of the question paper, you
are required to practice hard of the formulas and important topics. Some basic
concept on problem of ages, important illustrations and important shortcuts
tricks to crack Bank/SSC/UPSC
exams are given below so that you can prepare well and attempt all the
questions in examination.
Basic Concept for problems on ages
1) If the present age of ‘A’ is ‘x’ years, then
- ‘n’ years ago => Age of ‘A’ was (x-n) years.
- ‘n’ years after => Age of ‘A’ will be (x+n) years.
2) In general, at the starting of the solution we have to
assume the present age of one person. It is better to assume the present age =
‘x’ years.
3) So I advise you to assume the age of the younger person =
‘x’ years.
4) If the present age ‘A’ and ‘B’ are ‘x’ and ‘y’ years
respectively, then
- ‘n’ years ago => Age of ‘A’ and ‘B’ were (x-n) and (y-n) years respectively.
- ‘n’ years after => Age of ‘A’ and ‘B’ will be (x+n) and (y+n) years respectively.
5) The age difference between you and your friend is
let’s suppose 6 years. And after 10 or 15 years this will be same, because
clock will run equally for both of you.
Important Examples for Aptitude Section
Question 1- The age of the
father 3 years ago was 7 times the age of his son. At present, the father’s age
is five times that of his son. What are the present ages of the father and the
son?
Answer-
Let the present age of son = x yrs
Then, the present age of father =
5xyr
3 years ago,
7(x – 3) = 5x – 3
Or, 7x – 21 =5x – 3
Or, 2x =18
x = 9 yrs
Therefore, son’s age = 9 years
Father’s age = 45 years.
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Questions and Answers
Question 2- At present,
the age of the father is five times the age of his son. Three years hence, the
father’s age would be four times that of his son. Find the present ages of the
father and the son.
Answer-
Let the present age of son = x yrs
Then, the present age of father =
5x yrs
3 yrs hence,
4(x+3) = 5x+3
Or, 4x + 12=5x +3
x= 9yrs.
Therefore, son’s age = 9 yrs and
father’s age = 45 yrs.
Question 3- Three years
earlier, the father was 7 times as old as his son. Three years hence, the
father’s age would be four times of his son. What are the present ages of the
father and the son?
Answer-
Let the present age of son = x yrs and the present age of father = y yrs
3 yrs earlier, 7(x – 3) = y –
3 or, 7x – y =18…………. (i)
3 yes hence, 4(x+3) = y +3
Or, 4x +12 = y + 3 or, 4x – y = - 9 ………… (ii)
Solving (1) & (2) we get, x =
9 yrs & y =45 yrs.
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Question 4- The sum of the
ages of a mother and her daughter is 50 yrs. Also 5 yrs ago, the mother’s age
was 7 times the age of the daughter. What are the present ages of the mother
and the daughter?
Answer-
Let the age of the daughter be x yrs.
Then, the age of the mother is
(50x – x) yrs
5 yrs ago, 7(x – 5) = 50 – x – 5
Or, 8x = 50 – 5 +35 = 80
x =10
Therefore, daughter’s age = 10
yrs and mother’s age = 40yrs.
Question 5- The sum of the
ages of a son and father is 56 yrs. After 4 yrs, the age of the father will be
three times that of the son. What is the age of the son?
Answer-
Let the age of the son be x yrs.
Then, the age of the father is
(56 – x) yrs.
After 4 yrs, 3(x+4) = 56 – x +4
Or, 4x =56 +4 – 12 = 48
x = 12 yrs
Thus, son’s age = 12 yrs.
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Question 6- Lina got
married 8 years ago. Today her age is 9/7 time her age at the time of her
marriage. At present her daughter’s age is 1/6 of her age. What was her
daughter’s age 3 years ago?
Answer-
Let’s assume present age of Lina = x yrs.
Hence, x = (x-8) * 9/7 => x=36
years.
So present age of daughter = 1/6
* 36 => 6 years.
3 years age of daughter = 6-3 = 3
years.
Question 7- The age of
Rahul and Amit are in the ratio of 8:7. After 10 years the ratio of their ages
will be 13:12. What is the difference in years between their ages?
Answer-
Let’s assume the present age of Rahul and Amit = 8x and 7x
After 10 years,
(8x+10)/(7x+10) = 13/12
We get x=2 years.
So difference in age 8x – 7x = 16
– 14 = 2 years.
Question 8- The total age
of Ram and Shyam is 10 years more than that of total age of Shyam and Mohan.
Mohan is how many years younger than Ram?
Answer- R + S = S + M +10 => R
= M + 10 => M = R -10
Hence Mohan is 10 years younger
than Ram.
Important Formula for Ages Problems
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Final words:
Dear students, the above
information about Problem on age formulas and short tricks is for you all. Keep
practicing it daily so that you can rank well in the results. We the team of
www.privatejobshub.in, also wish to say all the very best to the aspirants who
are going to attend any competitive
exam.
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